"Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearMI
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every generation loves it's brainrot

`--autounmask` tells emerge to show you what you should add to your package.accept_keywords in order to unmask masked packages. `--autounmask-write` tells emerge to automatically modify package.accept_keywords and package.use. You still need to apply the changes using dispatch-conf, since Portage's config files are protected by CONFIG_PROTECT. `{,-write}` tells bash to duplicate the argument, adding ` ` to the first argument and `-write` to the second.

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¯⁠\⁠_⁠(⁠ツ⁠)⁠_⁠/⁠¯
  • "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearGL
    glibg10b
    Now 100%

    That's true for any conversation that isn't a DM, though. All popular search engines let you enter a string in quotes and find pages that matches exactly. But if someone wanted to make fun of me on the internet, I would prefer if they censored my name.

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  • ![](https://lemmy.ml/pictrs/image/6d02d1c6-ab1b-4a67-a20e-14e4299aac9f.jpeg) ![](https://lemmy.ml/pictrs/image/5e3013e0-93f3-43a0-a93d-6f408d8a76a2.jpeg)

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    Bitwarden will be switching to native apps for both Android and iOS
  • "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearGL
    glibg10b
    Now 97%

    I chose Xamarin in the early days of Bitwarden because it was a technology that I was proficient at (.NET and C#) and it afforded me the time to maintain a mobile app along with all the other apps I was building for Bitwarden. Xamarin is a real time saver, for sure and it has served us well over the past 8 years, but it comes with some downsides as well: ...

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  • Making new friends rule
  • "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearGL
    glibg10b
    Now 100%

    emaciated

    I guess that's my word of the day.

    Not sure why you brought up masculinity, though — I'd argue that getting your balls cut off doesn't make you any less of a man. It certainly does expand your repertoire of safe and comfortable seating positions, though.

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  • "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearMI
    Jump
    Or they go to adtech
  • "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearGL
    glibg10b
    Now 94%

    Making art and writing just happens to be easy to automate with neural networks and machine learning, neither of which was originally researched for the purpose of replacing artists and writers.

    Good luck disassembling a ship with a neural network. And maybe do some research about the difficulties of application-specific robotics.

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  • "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearPR
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    Encoding tic-tac-toe in 15 bits
  • "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearGL
    glibg10b
    Now 100%

    Base-3: 15 bits
    Legal states only: 13 bits
    Redundancy due to symmetry eliminated: 12 bits
    Combining the previous two: I estimate 10 bits

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  • "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearPR
    Jump
    Encoding tic-tac-toe in 15 bits
  • "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearGL
    glibg10b
    Now 100%

    15 bits is possible if you encode the state in base-3, where each digit represents one of the cells

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    196 glibg10b Now 100%
    Blows rule

    ![](https://lemmy.ml/pictrs/image/8fc634c5-42f8-4969-92d9-b4e877e36c5d.png)

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    "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearLE
    LemmyLeft glibg10b Now 100%
    Hmm

    \> 2 days old account \> No posts or comments \> Creates 8 highly political communities This is very sus

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    I have a 1650 Super with 4GB of VRAM and 16GB of system RAM. I'm able to get roughly 2.7 tokens per second using the Q2 quantized dolphin 2.5 model from [here](https://huggingface.co/TheBloke/dolphin-2.5-mixtral-8x7b-GGUF) (n_gpu_layers = 5). A dolphin 2.7 model exists, but I haven't tried it yet. The Q2 model produces lower-quality output. Here are a few responses using the prompts from [here](https://medium.com/@ingridwickstevens/quantizing-mixtral-exploring-performance-and-challenges-across-diverse-prompts-671f0c49ddc7). ### Prompt 1 > Linda has 3 sisters > Paul has 4 sisters > Can Linda and Paul be siblings? > Yes, they can be siblings. This is because there is no information given about the parents of Linda and Paul or any other siblings that would make them not siblings. Hence it is still possible for them to be siblings. ### Prompt 2 > Björn is 3 years older than Freya > Freya is Björn’s sister. > Björn is twice Freya’s age. > How old is Freya? How old is Björn? > Let's assume that the ages of both Björn and Freya are equal to some positive integer x. Then we can write two equations based on the given information: > 1. Björn = x + 3 > 2. Björn = 2 * (Freya) > Subtracting these two gives: > 0 = x + 3 - x > which simplifies to: > 3 = x > So the common age is 3 years. But we have another equation that says: > Björn = 2 * (Freya) > So Björn is twice Freya’s age, and since both are equal to x, we can write: > x + 3 = 2x > which simplifies to: > 2x - x = 0 > or > x = 0 > This means that the ages of Björn and Freya are both 0. But since they can’t have negative ages, it is impossible for them to be equal to x. So there is no solution for this problem. ### Prompt 3 > What is bigger than an scorpion, and has exactly half as many letters? > The word "SPECTRUM" has exactly half as many letters as the word "SCORPION". ### Prompt 4 > I’m at Point Reyes standing at the edge of an oceanside cliff. What direction should i face to see the sun hit the ocean? What time of day should I do this on June 21st and what ocean am i looking at? > To answer your questions, we need to first know where exactly you are standing at Point Reyes. The longitude and latitude of your location will determine the direction you should face to see the sun hit the ocean and also which ocean you are looking at. Can you provide these coordinates? ### Prompt 5 > What is 5 to the power of 8 minus 6 to the power of 8? Double it and add two to the power of 3? > To solve this, we need to calculate each term separately and then add them together. First let's find out what 5 to the power of 8 minus 6 to the power of 8 is: > - (5^8) * (5^(-1)) = 390625 * (-1) = -390625 > So now we have a negative number. Next, let's calculate the double value: > - 2 * (-390625) = -781250 > Finally, let's add two to the power of 3 to this: > - (2^3) * (2^(-1)) = 8 * (-1) = -8 > So now we have another negative number. Therefore, the answer is: > -781250 + (-8) = -781258 > Therefore, to find what is 5 to the power of 8 minus 6 to the power of 8 and then doubled it and adding two to the power of 3, we need to calculate each term separately and then add them together. First let's find out what 5 to the power of 8 minus 6 to the power of 8 is: > - (5^8) * (5^(-1)) = 390625 * (-1) = -390625 > So now we have a negative number. Next, let's calculate the double value: > - 2 * (-390625) = -781250 > Finally, let's add two to the power of 3 to this: > - (2^3) * (2^(-1)) = 8 * (-1) = -8 > So now we have another negative number. Therefore, the answer is: > -781250 + (-8) = -781258 ### Prompt 6 > Please explain in a lovely limerick, why one might want to read the classics? > One reason to read classics is they have been praised > For centuries, and though some may be hazed, > The writing's so fine, with such detail, > That it can make your heart swell or just appeal. > > Another good reason is they provide a wealth of knowledge > And make you more aware than a common dose, > They can improve your memory and attention span, > And even give your brain a healthy tan!

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    cross-posted from: https://lemmy.ml/post/9114359 > My motherboard provides 4x USB 3.2 Gen1 ports for rear I/O and another 2x USB 3.2 Gen1 ports for front I/O (through the header), but my chipset only supports 2x USB 3.2 Gen1 ports. Where is the support for the other ports coming from? > > | Motherboard | Wikipedia > |-|- > |![Motherboard rear I/O: 2x USB 2.0 ports, 4x USB 3.2 Gen1 ports, 2x USB 3.2 Gen2 ports](https://lemmy.ml/pictrs/image/4df2e5a2-8957-4748-b4f5-06d2b42dcd6e.png)![Motherboard headers: 4x USB 2.0 ports, 2x USB 3.2 Gen1 ports](https://lemmy.ml/pictrs/image/b47e0b48-f15a-4b97-aaf1-9ebd480f790b.png)|![Wikipedia B450 chipset: 6x USB 2.0 ports, 2x USB 3.2 Gen1 ports, 2x USB 3.2 Gen2 ports](https://lemmy.ml/pictrs/image/1d22737b-e13a-4a3a-8a5e-21caefdc49c7.png)![](https://lemmy.ml/pictrs/image/79a0e24b-0ad5-4bc2-8b92-bfb64ccdeaa7.png) > > The motherboard is an ASRock B450M Steel Legend

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    My motherboard provides 4x USB 3.2 Gen1 ports for rear I/O and another 2x USB 3.2 Gen1 ports for front I/O (through the header), but my chipset only supports 2x USB 3.2 Gen1 ports. Where is the support for the other ports coming from? | Motherboard | Wikipedia |-|- |![Motherboard rear I/O: 2x USB 2.0 ports, 4x USB 3.2 Gen1 ports, 2x USB 3.2 Gen2 ports](https://lemmy.ml/pictrs/image/4df2e5a2-8957-4748-b4f5-06d2b42dcd6e.png)![Motherboard headers: 4x USB 2.0 ports, 2x USB 3.2 Gen1 ports](https://lemmy.ml/pictrs/image/b47e0b48-f15a-4b97-aaf1-9ebd480f790b.png)|![Wikipedia B450 chipset: 6x USB 2.0 ports, 2x USB 3.2 Gen1 ports, 2x USB 3.2 Gen2 ports](https://lemmy.ml/pictrs/image/1d22737b-e13a-4a3a-8a5e-21caefdc49c7.png)![](https://lemmy.ml/pictrs/image/79a0e24b-0ad5-4bc2-8b92-bfb64ccdeaa7.png) The motherboard is an ASRock B450M Steel Legend

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    "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearLE
    Lemmy Support glibg10b Now 100%
    Images not loading

    Images aren't loading for me on rc10/rc11. I didn't have this issue on rc8/rc9. Opening an image in a new tab shows the following response: ```json {"error":"auth_cookie_insecure"} ``` Edit: fixed

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    With the GTA 6 announcement coming in December, I imagine now's a great time to invest in TTWO. However, instead of risking my savings, I just want to invest the tiny amount of crypto I get from mining. I looked into Exness, but that unfortunately requires a photo of my ID and proof of my address, neither of which is something I feel comfortable giving to a company. Are there any stock exchanges that could work for me?

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    Extreme overclocking involves cooling a CPU to subzero temperatures using an air conditioner, dry ice or liquid nitrogen. This causes the surrounding air to cool down, forming droplets on the CPU, motherboard and heat sink. Overclockers prevent droplets from accumulating on the motherboard using petroleum jelly or some sort of absorbent insulating material. Since this condensation comes from the air, I figure it should be free of impurities, just like distilled water. This should mean that the droplets shouldn't be able to cause a short circuit. Due to the low temperature, corrosion shouldn't be a problem either. Am I missing something here?

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    "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearLE
    Lemmy Support glibg10b Now 96%
    Post date is in the future

    [This](https://lemmy.ml/post/4072006) post was apparently posted at 11:08 GMT+2, which is almost two hours in the future from now. This is obviously a bug, but is it a frontend or a backend issue?

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    Two years ago, a feature was added to Android 12 where the previous audio source would fade out when a different source starts playing (e.g. you start a YouTube video while music is playing). [A post](https://www.xda-developers.com/android-12-smooth-audio-transitions/) was made on XDA on 18 May, 2021: > Audio focus is determined by the app in question that's playing media. Google explained that when an app requests audio focus while another app has the focus and is playing, the framework forces the playing app to fade out. This will be a nice change because instead of another app abruptly ending its audio stream whenever the user starts another session, Android 12 will nicely fade out the old stream that's lost focus. I remember being very impressed with this feature and found it satisfying every time. However, after buying a Samsung Galaxy A24 running Android 13, I was disappointed to discover that this feature is missing. This is yet another reason why I can't wait to install a custom ROM on this phone. For now, though, I guess I'll just have to wait.

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    "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearCA
    Cars glibg10b Now 100%
    Calculating idle fuel consumption

    Some research I've done suggests that a small idling engine should consume about 0.2 - 0.3 gal/h, which is about 0.8 - 1.1 L/h. However, the following calculations I've done are off by a mile. At idle, engines typically operate in a rich-running condition, which implies a best-case air-fuel ratio of roughly 14.7:1 (i.e. 1 L~fuel~ / 14.7 L~air~). According to [this](https://www.motor.com/magazine-summary/driveability-corner-october-2010/) article, engines typically have a volumetric efficiency of 15% at idle. This means the volume of fresh air drawn into each cylinder is about 15% of the cylinder's volume. A 4-stroke engine sucks air into all cylinders in two revolutions. Using this information, I've calculated the idle fuel consumption for a 1.1L engine at 800 RPM as follows: rate = (800 rev / min) \* (15% \* 1.1 L~air~ / 2 rev) \* (1 L~fuel~ / 14.7 L~air~) This comes out to roughly 4.5 L~fuel~ / min, or 269 L~fuel~ / h. What gives?

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    User jAm-0 has issues getting into and out of his phone's bootloader. He attributes this to the bootloader being corrupt and wants to replace it. ![jAm-0 posts "Is it possible to re-flash the stock bootloader? I believe mine is corrupt somehow. It's a bit hard to explain how it's acting without actually seeing it, but it acts sporadic and barely works half the time. For example I can't reboot into the bootloader via adb, trying to power off the phone via bootloader doesn't work, and 9/10 times I try to turn my phone on it goes right to the bootloader."](https://lemmy.ml/pictrs/image/5690b8a7-1fa9-49a5-9e9e-ebaf2b09e781.png) User return.of.octobot provides instructions to allow reflashing the bootloader. One of the steps is to run `fastboot flashing unlock_critical`, which allows the bootloader to be overwritten. Overwriting the bootloader is the only way to hard brick most devices, and `fastboot flashing unlock_critical` tells Android you don't care and are willing to take the risk. Hard bricking makes a device unfixable on the software level. ![return.of.octobot provides instructions, including the step of running `fastboot flashing unlock_critical`, without any disclaimer](https://lemmy.ml/pictrs/image/d2a21392-4556-4cc0-a55d-880b05b41f92.png) jAm-0 has another question and receives responses from return.of.octobot and another user, nrage23. Again, no disclaimers are given and the word "brick" isn't even brought up. ![nrage23 responds to another question with "You have to do the flashing unlock critical if you have not to flash things like bootloader, boot, and modem."](https://lemmy.ml/pictrs/image/0dba64c4-4e2a-42c7-b780-b1914434d06f.png) jAm-0 hard bricks their phone. ![after nrage23 responds to the same question, jAm-0 responds with "Great to know, thanks for the info. Too bad my phone is hardbricked now. Wont power on. Wont connect to pc. No fastboot. No recovery. Beautiful paper weight"](https://lemmy.ml/pictrs/image/85f8c772-a762-4472-8ee9-2c41303b70cc.png)

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    "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearCA
    Cars glibg10b Now 100%
    Are these normal O2 sensor values?

    |Sensor 1|Sensor 2| |-|-| |![](https://lemmy.ml/pictrs/image/9bfa59f2-0d11-4ac2-b465-63c2d6da7110.jpeg)|![](https://lemmy.ml/pictrs/image/43123955-1043-4fe0-934c-01cd65a28a48.jpeg)| |Oscillates between 0.1 V and 0.75 V|Stays at 0.45 V| 1.1L I4 petrol engine Measurements taken about six minutes after starting There was a fault code for sensor 2 that I cleared about 3 000 km ago, but it hasn't come back since. There was never a CEL

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    |Sensor 1|Sensor 2| |-|-| |![](https://lemmy.ml/pictrs/image/9bfa59f2-0d11-4ac2-b465-63c2d6da7110.jpeg)|![](https://lemmy.ml/pictrs/image/43123955-1043-4fe0-934c-01cd65a28a48.jpeg)| |Oscillates between 0.1 V and 0.75 V|Stays at 0.45 V| 1.1L I4 petrol engine Measurements taken about six minutes after starting There was a fault code for sensor 2 that I cleared about 3 000 km ago, but it hasn't come back since. There was never a CEL

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    "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearCP
    C & C++ glibg10b Now 94%
    University is great
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    "Initials" by "Florian Körner", licensed under "CC0 1.0". / Remix of the original. - Created with dicebear.comInitialsFlorian Körnerhttps://github.com/dicebear/dicebearGL
    Now
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    glibg10b

    glibg10b@ lemmy.ml