Question: Maybe is impossible to make std::begin (and friends) as friend function

Yes, it is probably a weird question, but I tried a lot, and I started to think that maybe is impossible to overload this template function properly:

#include <iterator>

class Foo
{
private:
    const int arr[5] = {10, 20, 30, 40, 50};
public:
    const int* begin() const { return arr; }

friend auto std::begin<>(const Foo &f) -> decltype(f.begin());
}

It always throw the same error (in GCC 12.2.0):

main.cxx:10:13: error: template-id ‘begin<>’ for ‘const int* std::begin<>(const Foo&)’ does not match any template declaration

I just wanna know if is possible do things like this. Thanks.